Alexander Zverev 0-2 Jannik Sinner

Finished

For this ATP Indian Wells match, BetFTW's top pick is Alexander Zverev to win, with a 58% model probability. We also predict over 2.5 sets at 48%.

How we calculate predictions

Bet For The Win

  1. Pick 1 Alexander Zverev to win L Settled - pick not won.
    Event probability
    58%
    Stake Med 49.0/100
    Odds 5.66 Fezbet Recorded P/L -49.60
    Best odds 6.00 Fezbet
  2. Pick 2 Total score over 2.5 L Settled - pick not won.
    Event probability
    48%
    Stake Low 22.4/100
    Odds 3.03 Pinnacle Recorded P/L -22.76
    Best odds 3.06 Pinnacle
Odds updated
Match analysis

Alexander Zverev vs Jannik Sinner prediction review

The final score was 0-2 when Alexander Zverev faced Jannik Sinner in ATP Indian Wells on Saturday, 14 March 2026.

BetFTW gives Alexander Zverev to win a 58% probability, making it the top-ranked pick for this event. The selection has latest recorded odds of 5.66 and falls into the Medium stake band. The selection was settled as a losing pick.

A second available pick comes from the total-sets market. For this market, over 2.5 sets carries a 48% model probability and latest recorded odds of 3.03. The predictions cover different markets, with the model assigning the higher probability to Alexander Zverev to win. The selection was settled as a losing pick.

The best price recorded for the primary pick is 6.00, above its latest recorded odds of 5.66. The page preserves the model probability, best and latest recorded odds, stake band and result to provide a transparent historical record.